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Homework Chapter 2

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2021-02-13 06:47
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2021年2月13日发(作者:capeverde)



Computer Networks and Internet




Chapter 2


1.


Consider


the


following


string


of


ASCII


characters


that


were


captured


by


Wireshark when the browser sent an HTTP GET message (i.e., this is the actual


content of an HTTP GET message). The characters are carriage return


and line-feed characters (that is, the italized character string in the text below


represents the single carriage-return character that was contained at that point in


the HTTP header). Answer the following questions, indicating where in the HTTP


GET message below you find the answer.



GET /cs453/ HTTP/1.1Host: User-Agent:


Mozilla/5.0 (Windows;U; Windows NT 5.1; en-US; rv:1.7.2) Gecko/20040804 Netscape/7.2 (ax)


Accept:ext/xml, application/xml, application/xhtml+xml, text/html;q=0.9,


text/plain;q=0.8,image /png,*/*;q=0.5Accept-Language:


en-us,en;q=0.5Accept-Encoding: zip,deflateAccept-Charset:


ISO- 8859-1,utf-8;q=0.7,*;q=0.7Keep-Alive:


300Connection:keep- alive



a. What is the URL of the document requested by the browser?


b. What version of HTTP is the browser running?


c. Does the browser request a non-persistent or a persistent connection?


d. What is the IP address of the host on which the browser is running?


e. What type of browser initiates this message? Why is the browser type needed in an


HTTP request message?


考虑以下的< /p>


ASCII


字符字符串被


Wiresha rk


当浏览器发送一个


HTTP GET


消息


(


即。


,


这是一个


HTTP GET


消息的实际


内容


)


。字符


< cr > < >


如果是回车和换行符字符


(



italized


下面的文本字符串


< cr >


代表单一回车字符包含在


这一点上的


HTTP



)


。回答下列问题


,


表明在


HTTP GET


消息下面你找到答案。



a


。什么是文档的


URL


请求的浏览器


?


b


。浏览器运行


HTTP


版本是什么


?


c

< p>
。浏览器请求一个非持久性或持久连接


?


d


。什么是浏览器的


IP


地址的主机运行吗< /p>


?


e


。什么样的浏览器启动这个消息吗


?


为什么浏览器类型所需的


HTTP< /p>


请求消息吗


?



1


浏览器类型信息需要由服务器发送同一对象的不同版本


,


不同类型的浏览器。



2. The text below shows the reply sent from the server in response to the HTTP GET


message in the question above. Answer the following questions, indicating where in


the message below you find the answer.



HTTP/1.1 200 OK



Date: Tue, 07 Mar 2008 12:39:45GMT



Server: Apache/2.0.52


(Fedora) Last- Modified: Sat, 10 Dec2005 18:27:46 GMT



ETag:


526c3-f22-


a88a4c80”


< /p>


Accept-Ranges: bytes



Content-Length:


3874



Keep- Alive: timeout=max=100


Connection: Keep- Alive



Content-Type:


text/html; charset=ISO-8859-1




-//w3c//dtd html 4.0


transi tional//en”>








equiv=”Content


-


Type”content=”text/html;

< p>
charset=iso-8859-


1”>




U) Netscape]”>



CMPSCI 453 / 591 /NTU-ST550A Spring 2005 </p><p><br>homepage





<< /p>


much more document text following here (not shown)


>



a.


Was


the


server


able


to


successfully


find


the


document


or


not?


What


time


was


the


document reply provided?


b. When was the document last modified?


c. How many bytes are there in the document being returned?


d. What are the first 5 bytes of the document being returned? Did the server agree to a


persistent connection?


下面的文本显示来自服务器的应答发送响应


HTTP


GET


消息在上面的问题中。回答下列问题


,< /p>


显示下面的消息


,


找到答案。



一个。服务器能够成功地找到文档吗


?


文档回复提供时间是什么


?


b


。最后修改的文档是什么时候


?


c


。有多少字节的文档返回


?


d


。第一个是什么


5


字节的文档返回


?


服务器同意一个持久连接吗

< br>?





3. Consider following Figure, for which there is an institutional network connected to


the


Internet.


Suppose


that


the


average


object


size


is


900kb


and


that the


average


re


quest rate from the institution’s browsers to the origin servers is 1


5 requests per


second. Also suppose that the amount of time it takes from when the router on the


Internet


side


of


the


access


link


forwards


an


HTTP


request


until


it


receives


the


response is 3s on average. Model the total average response time as the sum of the


average access delay (that is, the delay from Internet router to institution router)


and the average


Internet delay. For the average access delay, use Δ/(1–Δ


β


), where


Δ is the


average time required to send an object over the access link and


β



is the


arrival rate of objects to the access link.


2



Figure 1



Bottleneck between an institutional network and the Internet


a. Find the total average response time.


b. Now suppose a cache is installed in the institutional LAN. Suppose the miss rate is


0.4. Suppose hit rate increases to 0.95. Find the total response time. < /p>


考虑下面的图


,


有一个机构网络连接到互 联网。


假设对象的平均尺寸是


900 kb,

< br>平均请求率从机构的浏览器起源


服务器每秒


15


请求。


还假设的时间在互联网上需要从路由器的访问链接转发

< p>
HTTP


请求


,


直到接收 到响应平均


3


s


。模型总平均响应时 间平均访问延迟之和


(


即延迟从互联网路由器到路由器


)


机构和平均网络延迟。平均


访问延迟


,


使用


Δ/(1


-


Δβ),Δ


发送对象所需的平均时间的访问链接和

< br>β


的到达率是对象的访问链接。



发现总平均响应时间。



b

< p>
。现在假设一个缓存是安装在机构局域网。想错过率是


0.4


。假设命中率增加到


0.95


。发现总响应时间。< /p>




4. Print out the header of an e-mail message you have recently received. How many


Received


: header lines are there? Analyze each of the header lines in the message.


(Allow printing of an email header file.)


打印头你最近收到的一封电子 邮件。多少接受


:


头行吗


?

< p>
分析每个头线的消息。


(


允许打印头文件的电子邮 件。


)


3



5.


Read


RFC


5321


for


SMTP.


What


does


MTA


stand


for?


Consider


the


following


received


spam


email


(modified


from


a


real


spam


email).


Assuming


only


the


originator of this spam email is malacious and all other hosts are honest, identify


the malacious host that has generated this spam email.



SMTP



RFC 5321



MT A


代表什么


?


考虑以下收到垃圾邮件从 一个真正的垃圾邮件


(


修改


)


。假设只


malacious


这个垃圾邮件的发 起者和所有其他主机是诚实的


,


识别


m alacious


主机生成的这个垃圾邮件。



From - Fri Nov 07 13:41:30 2008


Return-Path:


Received: from


( [128.119.240.3]) by (8.13.1/8.12.6) for ; Fri, 7


Nov 2008 13:27:10 -0500


Received:


from


asusus-4b96


(localhost


[127.0.0.1])


by



(Spam


Firewall)


for


; Fri, 7 Nov 2008 13:27:07 -0500 (EST)


Received: from asusus-4b96 ([58.88.21.177]) by for ; Fri, 07


Nov 2008 13:27:07 -0500 (EST)


Received: from [58.88.21.177] by Sat, 8 Nov 2008 01:27:07 +0700


From:


To:


Subject: How to secure your savings



MTA stands for Mail Transfer Agents. A mail is forwarded by a source to a MTA and then it follows a


sequence of MTAs to reach the receiver’s mail reader.



We see that this spam email follows a chain of


MTAs.


An


honest


MTA


should


report


where


it


receives


the


message.


Notice


that


in


this


email,


“asusus


-


4b96 ([58.88.21.177])” does not report where it receives the email. As we assume that the only


the originator is dishonest, so “asusus


-


4b96 ([58.88.21.177])” must be the originator.



MTA


代表 邮件传输代理。邮件转发由源到


MTA


然后遵循一系列放在到达 接收方的邮件阅读器。我们看到这个垃


圾邮件之前放在链。一个诚实的

< br>MTA


应该报告接收消息。注意


,


在这封邮件中


,“asusus


-


4 b96([58.88.21.177])“



报告接收电子邮 件。当我们假定唯一的发起人是不诚实的


,


所以


“asusus


-


4b96([58.88.21.1 77])”


必须发起人。



6.


Answer


the


following


question,


using


the


WHOIS


Tools


(such


as,


SmartWhois,


WhereIsIP ,CountryWhois, /) and nslookup.


a. What is a whois database?


b. Use various whois databases on the Internet to obtain the names of two DNS servers.


Indicate which whois databases you used. (such as, , ,


, )


c.


Use


nslookup


on


your


local


host


to


send


DNS


queries


to


three


DNS


servers:


your


local DNS server and the two DNS servers


you found in part (b). Try querying for


Type A, NS, and MX reports. Summarize your findings.


d.


Use


nslookup


to


find


a


Web


server


that


has


multiple


IP


addresses.


Does


the


Web


server of BUPT have multiple IP addresses?


e.


Use


the


ARIN


whois


database


to


determine


the


IP


address


range


used


by


your


institution (such as,. , , ).

回答下列问题


,


使用


WHOIS< /p>


工具


(



Sma rtWhois


WhereIsIP


,CountryWho is,/)


和网路资讯


查询。



4

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